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nilpotent ring

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Lecture Notes on Bayesian Estimation and Classification Mário A T Figueiredo

《Lecture Notes on Bayesian Estimation and Classification》 · 第 127 页 · Chapter 5,Section 5.1「Abelian and Central Series」,小节「Triangular and Unitriangular Groups」

Let $S$ be a ring with identity and let $N$ be a subring of $S$. Write $N^{(i)}$ for the set of all sums of products of $i$ elements of $N$ where $i>0$; clearly $N^{(i)}$ is a subring. Also $N^{(i)}=0$ if and only if all products of $i$ elements of $N$ vanish. If some $N^{(i)}$ equals $0$, then $N$ is said to be nilpotent.

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